32x^2+28x^2+5x=0

Solution for 32x^2+28x^2+5x=0 equation:

32x^2+28x^2+5x=0

We add all the numbers together, and all the variables

60x^2+5x=0

a = 60; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·60·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*60}=\frac{-10}{120}
=-1/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*60}=\frac{0}{120}
=0
$